Optimal. Leaf size=97 \[ -\frac{3 i x \text{PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^3}+\frac{3 \text{PolyLog}\left (3,e^{2 i (a+b x)}\right )}{2 b^4}+\frac{3 x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b^2}-\frac{x^3 \cot (a+b x)}{b}-\frac{i x^3}{b}-\frac{x^4}{4} \]
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Rubi [A] time = 0.177727, antiderivative size = 97, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.583, Rules used = {3720, 3717, 2190, 2531, 2282, 6589, 30} \[ -\frac{3 i x \text{PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^3}+\frac{3 \text{PolyLog}\left (3,e^{2 i (a+b x)}\right )}{2 b^4}+\frac{3 x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b^2}-\frac{x^3 \cot (a+b x)}{b}-\frac{i x^3}{b}-\frac{x^4}{4} \]
Antiderivative was successfully verified.
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Rule 3720
Rule 3717
Rule 2190
Rule 2531
Rule 2282
Rule 6589
Rule 30
Rubi steps
\begin{align*} \int x^3 \cot ^2(a+b x) \, dx &=-\frac{x^3 \cot (a+b x)}{b}+\frac{3 \int x^2 \cot (a+b x) \, dx}{b}-\int x^3 \, dx\\ &=-\frac{i x^3}{b}-\frac{x^4}{4}-\frac{x^3 \cot (a+b x)}{b}-\frac{(6 i) \int \frac{e^{2 i (a+b x)} x^2}{1-e^{2 i (a+b x)}} \, dx}{b}\\ &=-\frac{i x^3}{b}-\frac{x^4}{4}-\frac{x^3 \cot (a+b x)}{b}+\frac{3 x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b^2}-\frac{6 \int x \log \left (1-e^{2 i (a+b x)}\right ) \, dx}{b^2}\\ &=-\frac{i x^3}{b}-\frac{x^4}{4}-\frac{x^3 \cot (a+b x)}{b}+\frac{3 x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b^2}-\frac{3 i x \text{Li}_2\left (e^{2 i (a+b x)}\right )}{b^3}+\frac{(3 i) \int \text{Li}_2\left (e^{2 i (a+b x)}\right ) \, dx}{b^3}\\ &=-\frac{i x^3}{b}-\frac{x^4}{4}-\frac{x^3 \cot (a+b x)}{b}+\frac{3 x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b^2}-\frac{3 i x \text{Li}_2\left (e^{2 i (a+b x)}\right )}{b^3}+\frac{3 \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^4}\\ &=-\frac{i x^3}{b}-\frac{x^4}{4}-\frac{x^3 \cot (a+b x)}{b}+\frac{3 x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b^2}-\frac{3 i x \text{Li}_2\left (e^{2 i (a+b x)}\right )}{b^3}+\frac{3 \text{Li}_3\left (e^{2 i (a+b x)}\right )}{2 b^4}\\ \end{align*}
Mathematica [A] time = 0.845438, size = 171, normalized size = 1.76 \[ \frac{6 i b x \text{PolyLog}\left (2,-e^{-i (a+b x)}\right )+6 i b x \text{PolyLog}\left (2,e^{-i (a+b x)}\right )+6 \text{PolyLog}\left (3,-e^{-i (a+b x)}\right )+6 \text{PolyLog}\left (3,e^{-i (a+b x)}\right )-\frac{2 i b^3 x^3}{-1+e^{2 i a}}+3 b^2 x^2 \log \left (1-e^{-i (a+b x)}\right )+3 b^2 x^2 \log \left (1+e^{-i (a+b x)}\right )}{b^4}+\frac{x^3 \csc (a) \sin (b x) \csc (a+b x)}{b}-\frac{x^4}{4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.149, size = 231, normalized size = 2.4 \begin{align*} -{\frac{{x}^{4}}{4}}-{\frac{2\,i{x}^{3}}{b \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}-1 \right ) }}-{\frac{2\,i{x}^{3}}{b}}-3\,{\frac{\ln \left ( 1-{{\rm e}^{i \left ( bx+a \right ) }} \right ){a}^{2}}{{b}^{4}}}+3\,{\frac{\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}+1 \right ){x}^{2}}{{b}^{2}}}-{\frac{6\,i{\it polylog} \left ( 2,-{{\rm e}^{i \left ( bx+a \right ) }} \right ) x}{{b}^{3}}}+6\,{\frac{{\it polylog} \left ( 3,-{{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{4}}}+3\,{\frac{\ln \left ( 1-{{\rm e}^{i \left ( bx+a \right ) }} \right ){x}^{2}}{{b}^{2}}}-{\frac{6\,i{\it polylog} \left ( 2,{{\rm e}^{i \left ( bx+a \right ) }} \right ) x}{{b}^{3}}}+6\,{\frac{{\it polylog} \left ( 3,{{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{4}}}+3\,{\frac{{a}^{2}\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}-1 \right ) }{{b}^{4}}}-6\,{\frac{{a}^{2}\ln \left ({{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{4}}}+{\frac{4\,i{a}^{3}}{{b}^{4}}}+{\frac{6\,i{a}^{2}x}{{b}^{3}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 2.115, size = 1287, normalized size = 13.27 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 1.79655, size = 971, normalized size = 10.01 \begin{align*} -\frac{b^{4} x^{4} \sin \left (2 \, b x + 2 \, a\right ) + 4 \, b^{3} x^{3} \cos \left (2 \, b x + 2 \, a\right ) + 4 \, b^{3} x^{3} + 6 i \, b x{\rm Li}_2\left (\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right )\right ) \sin \left (2 \, b x + 2 \, a\right ) - 6 i \, b x{\rm Li}_2\left (\cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right )\right ) \sin \left (2 \, b x + 2 \, a\right ) - 6 \, a^{2} \log \left (-\frac{1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) + \frac{1}{2} i \, \sin \left (2 \, b x + 2 \, a\right ) + \frac{1}{2}\right ) \sin \left (2 \, b x + 2 \, a\right ) - 6 \, a^{2} \log \left (-\frac{1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) - \frac{1}{2} i \, \sin \left (2 \, b x + 2 \, a\right ) + \frac{1}{2}\right ) \sin \left (2 \, b x + 2 \, a\right ) - 6 \,{\left (b^{2} x^{2} - a^{2}\right )} \log \left (-\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right ) \sin \left (2 \, b x + 2 \, a\right ) - 6 \,{\left (b^{2} x^{2} - a^{2}\right )} \log \left (-\cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right ) \sin \left (2 \, b x + 2 \, a\right ) - 3 \,{\rm polylog}\left (3, \cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right )\right ) \sin \left (2 \, b x + 2 \, a\right ) - 3 \,{\rm polylog}\left (3, \cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right )\right ) \sin \left (2 \, b x + 2 \, a\right )}{4 \, b^{4} \sin \left (2 \, b x + 2 \, a\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{3} \cot ^{2}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{3} \cot \left (b x + a\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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